tentukam titik beku larutan yg mengandung 18 gram glukosa (Mr=180) dalam 250 gram air. Kf air= 1,86°C/m

delta Tf = m*kf
= (massa glukosa/Mr)*(1000/p)*kf
= (18/180)*(1000/250)*1,86
= 0,774 derajat celcius
Tf glukosa = Tf air - delta Tf
= 0-0,774
= -0,774 derajat celcius