Berapakah massa zat terlarut pada larutan 200 mL larutan CH3COOH 0,4 M? ( Ar C = 12: O = 16: H = 1)

M = mol / volume
M = massa / Mr / volume
massa = M x Volume x Mr
massa = 0,4 x 0,2 x 60
massa = 4,8 gr