Berapa diameter kaleng tersebut

V = TT . r.r.t
2.009,6= 3.14. r. r . 10
2.009,6= 31.4 r . r.
r kuadrat = 2009.6÷ 31.4
r kuadrat = 64
r = akar dari 64
r = 8
Diameter = 2X r
Diameter = 2x 8
Diameter=16

Volume kaleng = pi x r^2  x t
2.009,6 = 3,14 x 10 x r^2
r = akar 68 = 8 maka
diameter = 2r = 2 x 8 = 16 cm