Matematika

Pertanyaan

No 6-8 harap bantuannyaaa
No 6-8 harap bantuannyaaa

2 Jawaban

  • 6) U5 = 500
    a + 4 b = 500
    U12 = 850
    a + 11 b = 850
    ( a + 4b ) + 7b = 850
    ( 500 ) + 7b = 850
    ' 7b = 850 - 500
    7b = 350
    ' b = 350/7 = 50
    a + 4b = 500
    a +4.50 = 500
    a + 200 = 500
    a = 500 - 200 = 300
    7) a = 100, r = 2, n = 3 jam /15 menit = 12
    Sn = a ( r^n - 1 ) / ( r 1 )
    S12 = 100 ( 2^12 - 1 ) / ( 2-1 )
    = 100 ( 4.096 - 1 ) / 1
    = 100 ( 4.095 )
    = 409.500
    8) a = 5, U6 = ar^5 = 1.215
    5.r^5 = 1.215
    r^5 = 243
    r^5 = 3^5
    r = 3
    Sn = a ( r^n - 1 ) / ( r - 1 )
    S6 = 5 ( 3^6 - 1 ) / ( 3 - 1 )
    = 5 ( 729 - 1 ) / 2
    = 5 x 364
    = 1.820 cm



    .
  • 6.
    U₅ = 500
    U₁₂ = 850

    Rumus cepat mencari beda
    [tex] b = \frac{U_{12}-U_{5}}{12-5} [/tex]
    [tex] b = \frac{850-500}{7} [/tex]
    [tex] b = \frac{350}{7} [/tex]
    b = 50

    [tex] U_5 = a + 4b [/tex]
    500 = a + 4(50)
    a = 500 - 200
    a = 300
    Jadi produksi telur hari pertama = 300 butir

    7.
    n = 3 jam = 3 x 60 = 180 menit
    p = 180 : 15 = 12 kali
    a = 100
    r = 2

    [tex] U_p = ar^p[/tex]
    =>100 • 2¹²
    =>100 • 4096
    =>409600

    8.
    [tex] U_1 = 5 , U_6 = 1215 [/tex]
    Rumus cepat rasio

    [tex] r = (\frac{U_6}{U_1})^{\frac{1}{6-1}}
    [/tex]
    [tex]r = (\frac{1215}{5})^{\frac{1}{5}} [/tex]
    [tex] r = \sqrt[5]{243} [/tex]
    r = 3

    Maka
    [tex] Sn = \frac{a(r^n-1)}{r-1} [/tex]
    [tex] S_6 = \frac{5(3^6-1)}{(3-1)} [/tex]
    [tex] S_6 = \frac{5(728)}{2} [/tex]
    [tex] S_6 = 5 \times 364 [/tex]
    =>1820 cm