Matematika

Pertanyaan

F(y) = y2+5y+3
Tentukan:
F(2)
F(3)
F(4)
F(5)
F(6)

1 Jawaban

  • f(y) = y² + 5y + 3
    f(2) = 2² + 5*2 + 3 = 4 + 10 + 3 = 17
    f(3) = 3² + 5*3 + 3 = 9 + 15 + 3 = 27
    f(4) = 4² + 5*4 + 3 = 16 + 20 + 3 = 39
    f(5) = 5² + 5*5 + 3 = 25 + 25 + 3 = 53
    f(6) = 6² + 5*6 + 3 = 36 + 30 + 3 = 69

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