jika f'(x)=36(2x-5) dan f(2)=10 maka f(x)=

f'(x) = 72x-180
f(x) = ∫f'(x) dx
f(x) = ∫(72x-180) dx
f(x) =36x²-180x+c
f(2) = 36(2)²-180(2) + c
10 = 144 - 360 +c
c = -226
f(x) = 36x²-180x-226
selesai