Matematika

Pertanyaan

f (y)= y2+5y+3
Tentukan:
F(2)
F(3)
F(4)
F(5)
F(6)

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2 Jawaban

  • F(2)=2.2+5.2+3
    =4+10+3=17

    F(3)=3.2+5.3+3
    =6+15+3
    =24

    F(4)=4.2+5.4+3
    =8+20+3
    =31

    F(5)=5.2+5.5+3
    =10+25+3
    38

    F(6)=6.2+5.6+3
    =12+30+3
    =45

  • F (y)= y2+5y+3
    Tentukan:
    F(2)
    F(3)
    F(4)
    F(5)
    F(6)


    F(2) = (2)2+5(2)+3 = 4+10+3 = 17

    F(3) = (3)2+5(3)+3 = 6+15+3 = 24

    F(4) = (4)2+5(4)+3 = 8+20+3 = 31

    F(5) = (5)2+5(5)+3 = 10+25+3 = 38

    F(6) = (6)2+5(6)+3 = 12+30+3 = 45






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