Tolong jawab pertanyaan dibawah ini dengan benar (pakai rumus) Gunakan rumus definisi [tex]^a{log} x = n (=) a^n = x [/tex] [tex]^6{log} 8 x^{2} + 3x + 12 =

jawab
⁶log (8x² + 3x +12) = 2 → 8x² + 3x + 12 = 6²
8x² + 3x + 12 = 36
8x² + 3x  = 24
x² + 3/8 x = 3
(x + 3/16)² = 3 + 9/256
(x + 3/16)² = 777/256
x + 3/16 = 1/16 √777
x = 3/16  + 1/16 √777 = 1/16( 3 + √777)
x = 3/16 - 1/16 √777  = 1/16 (3 - √777)