4^log(x+6) - 4^logx =2 Tentukan nilai x
Matematika
Chaniee99
Pertanyaan
4^log(x+6) - 4^logx =2
Tentukan nilai x
Tentukan nilai x
1 Jawaban
-
1. Jawaban Anonyme
jawab
⁴log (x + 6) - ⁴log x = 2
⁴log (x +6)/(x) = 2
(x+6)/ (x) = 4²
(x+6) / (x) = 16
(x+6) = 16(x)
x + 6 = 16 x
x - 16 x = - 6
-15x =- 6
x = 6/15
x = 2/5