Tentang Fungsi Invers....(ada digambar) Tolong Dijawab....!!!

g(x) = √(x-5)
y = √(x-5)
y² = x - 5
x = y² + 5
Jadi
g⁻¹(x) = x² + 5


h(x) = (x+3) / (x-2)
y = (x+3) / (x-2)
y(x-2) = x+3
xy - 2y = x + 3
xy - x = 2y + 3
x(y - 1) = 2y - 3
x = (2y-3) / (y-1)
Jadi
h⁻¹(x) = (2x-3) / (x-1)