Matematika

Pertanyaan

R:7 cm timggi21 cm phi 22/7
A. Tehtukan luas selimut tabung
B. Luas tabung tanpa yutup
C. LuaS tabung
D volume tabung

1 Jawaban

  • A. L = 2 × phi × r × t

    = 2 × 22/7 × 7 × 21

    = 2 × 22 × 7 × 3

    = 44 × 21

    = 924 cm^2


    B. L = phi × r × (r + 2 × t)

    = 22/7 × 7 × (7 + 2 × 21)

    = 22 × 1 × (7 + 42)

    = 22 × 1 × 49

    = 1.078 cm^2


    C. L = phi × r^2

    = 22/7 × 7^2

    = 22/7 × 49

    = 22 × 7

    = 154 cm^2


    D. V = phi × r^2 × t

    = 22/7 × 7^2 × 21

    = 22/7 × 49 × 21

    = 22 × 7 × 21

    = 3.234 cm^2

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