Hasil integral batas atas 4 batas bawah 2 (-x² + 6x - 8) dx=
Matematika
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Pertanyaan
Hasil integral batas atas 4 batas bawah 2 (-x² + 6x - 8) dx=
1 Jawaban
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1. Jawaban Anonyme
InTegraL
∫(-x² + 6x - 8) dx [4...2]
= -x³/3 + 6x²/2 - 8x
= -1/3 x³ + 3x² - 8x
= (-1/3 . 4³ + 3.4² - 8.4) - (-1/3 . 2³ + 3.2² - 8.2)
= -64/3 + 8/3 + 16 + 4
= -56/3 + 20
= -18 2/3 + 20
= 1 1/3