Matematika

Pertanyaan

tolong dijawab yahh kak
tolong dijawab yahh kak

1 Jawaban

  • Diketahui :
    Jari - Jari = 28 cm
    Luas Kerucut = 5.544 cm²
    π = 22/7

    Ditanya :
    a. s = ....?
    b. t = ....?
    c. V = ....?

    Penyelesaian :
    a. Garis Pelukis
    Luas Kerucut = πr (r + t)
    5.544 = 22/7 × 28 (28 + t)
    5.544 = 22 × 4 (28 + t)
    5.544 = 88 (28 + t)
    5.544 = 2.464 + 88t
    5.544 - 2.464 = 88t
    3080 = 88t
    35 = t
    t = 35 cm

    s = √t² + r²
    s = √35² + 28²
    s = √1.225 + 784
    s = √2009
    s = 7√41 cm

    b. Tinggi Kerucut
    Luas Kerucut = πr (r + t)
    5.544 = 22/7 × 28 (28 + t)
    5.544 = 22 × 4 (28 + t)
    5.544 = 88 (28 + t)
    5.544 = 2.464 + 88t
    5.544 - 2.464 = 88t
    3080 = 88t
    35 = t
    t = 35 cm

    c. Volume Kerucut
    Volume = ⅓ × π × r² × t
    = ⅓ × 22/7 × 28² × 35
    = ⅓ × 22/7 × 784 × 35
    = ⅓ × 22 × 112 × 35
    = ⅓ × 22 × 3.920
    = ⅓ × 86.240
    = 28.746,6667 cm³