tolong dijawab yahh kak
Matematika
audy130
Pertanyaan
tolong dijawab yahh kak
1 Jawaban
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1. Jawaban Arkan5283
Diketahui :
Jari - Jari = 28 cm
Luas Kerucut = 5.544 cm²
π = 22/7
Ditanya :
a. s = ....?
b. t = ....?
c. V = ....?
Penyelesaian :
a. Garis Pelukis
Luas Kerucut = πr (r + t)
5.544 = 22/7 × 28 (28 + t)
5.544 = 22 × 4 (28 + t)
5.544 = 88 (28 + t)
5.544 = 2.464 + 88t
5.544 - 2.464 = 88t
3080 = 88t
35 = t
t = 35 cm
s = √t² + r²
s = √35² + 28²
s = √1.225 + 784
s = √2009
s = 7√41 cm
b. Tinggi Kerucut
Luas Kerucut = πr (r + t)
5.544 = 22/7 × 28 (28 + t)
5.544 = 22 × 4 (28 + t)
5.544 = 88 (28 + t)
5.544 = 2.464 + 88t
5.544 - 2.464 = 88t
3080 = 88t
35 = t
t = 35 cm
c. Volume Kerucut
Volume = ⅓ × π × r² × t
= ⅓ × 22/7 × 28² × 35
= ⅓ × 22/7 × 784 × 35
= ⅓ × 22 × 112 × 35
= ⅓ × 22 × 3.920
= ⅓ × 86.240
= 28.746,6667 cm³