jika diketahui Log 2=0,3010 dan Log 3=0,4771 hitunglah Log 12 dan Log 18

log 12=log2^2x3
=log 2^2+log 3
=2.log 2+log3
=2.0,3010 + 0,4771
=1,0791
log2x3^2
=log 2+ 2.log 3
=0,301 + 2.0,4771
=1,2552

Log 12
= log (2².3)
= log 2² + log 3
= 2 log 2 + log 3
= 2 . 0,3010 + 0,4771
= 0,6020 + 0,4771
= 1,0791

Log 18
= log (3².2)
= log 3² + log 2
= 2 log 3 + log 2
= 2 . 0,4771 + 0,3010
= 0,9542 + 0,3010
= 1,2552

Jadikan terbaik yaa. Thanks.